Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given"egg"
, "add"
, return true. Given "foo"
, "bar"
, return false.
Given "paper"
, "title"
, return true.
132/155
思路:two hashmap一一对应字母。
public class Solution { public boolean isIsomorphic(String s, String t) { if(s.length()!=t.length()||s==null || t==null) return false; Mapres1=new HashMap<>(); Map res2=new HashMap<>(); for(int i=0;i<=s.length()-1;i++){ if(!res1.containsKey(s.charAt(i))){ res1.put(s.charAt(i),t.charAt(i)); }else{ if(res1.get(s.charAt(i))!=t.charAt(i))return false; } if(!res2.containsKey(t.charAt(i))){ res2.put(t.charAt(i),s.charAt(i)); }else{ if(res2.get(t.charAt(i))!=s.charAt(i))return false; } } return true; }}